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-2x^2=-9x+9
We move all terms to the left:
-2x^2-(-9x+9)=0
We get rid of parentheses
-2x^2+9x-9=0
a = -2; b = 9; c = -9;
Δ = b2-4ac
Δ = 92-4·(-2)·(-9)
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-3}{2*-2}=\frac{-12}{-4} =+3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+3}{2*-2}=\frac{-6}{-4} =1+1/2 $
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